WebFeb 28, 2013 · In an A.P. the sum of first ten terms is –80 and the sum of next ten terms is –280. Find the A.P WebThe third term of an AP is four times the sixth term and the sum of the first ten terms is 150. Find a) The first term and the common difference b) The least number of terms of the Arithmetic Progression which must be taken for the sum to be negative Expert Solution Want to see the full answer? Check out a sample Q&A here See Solution star_border

Answered: Use the sum of the first ten terms to… bartleby

WebMar 23, 2024 · Since we know that the sum of the first n terms of an A.P. is S n = n 2 [ 2 a + ( n − 1) d] where ‘a’ is the first term and ‘d’ is common difference. We have n=10 and S n = − 150 . ⇒ − 150 = 10 2 [ 2 a + ( 10 − 1) d] ⇒ − 150 = 5 [ 2 a + 9 d] ⇒ − 150 5 = 2 a + 9 d ⇒ − 30 = 2 a + 9 d..... ( 1) Now the sum of the next ten terms is -550. happy tails palmyra va

Answered: The third term of an AP is four times… bartleby

WebIn an AP, the sum of first ten terms is −150 and the sum of its next ten terms is −550. Find the AP. Medium Solution Verified by Toppr S 10=−150 S n= 2n[2a+(n−1)d] S 10= … WebJun 24, 2024 · The AP is 3, - 1,- 5 ,- 9,…... Step-by-step explanation: Given : S10 = - 150 and sum of its next 10 terms is - 550. By using the formula ,Sum of nth terms , Sn = n/2 [2a + (n – 1) d] S10 = (10/2) [ 2a + (10 - 1)d ] -150 = 10/2 [2a + 9d] -150 = 5 [2a + 9d] -150/5 = 2a + 9d - 30 = 2a + 9d 2a + 9d = - 30 ………... (1) And WebSum In an A.P., the sum of first ten terms is −150 and the sum of its next ten terms is −550. Find the A.P. Advertisement Remove all ads Solution Here, we are given S 10 = -150 and sum of the next ten terms is −550. Let us take the first term of the A.P. as a and the common difference as d. So, let us first find a10. happy tails pet sitting